(Q8) The angle of elevation of the top of a building from the foot of the tower is 30o and the angle of elevation of the top of the tower from the foot of the building is 60o. If the tower is 30 m high, find the height of the building.

Solution :

60°30°30 mxdTower

Height of the tower = 30 m

Angle of elevation of the top of the tower = 60°.

Angle of elevation of the top of the building = 30°

Let the distance between the foot of the tower and foot of the building be d m and height of the building be x m.

From the figure

tan 60° =
d
=
d
d =
=
×√3×√3
= m
Also tan 30° =
x
d

Put d value

1
=
x
x =
= m

∴ Height of the building = m